MM of CaCl_{2 }is 110.98 g/mol; MM of CaCO_{3} is 100.09 g/mol; MM of HCl is 35.46 g/mol

g CaCl_{2} from CaCO_{3}

$\mathbf{g}\mathbf{}{\mathbf{CaCl}}_{\mathbf{2}}\mathbf{}\mathbf{=}\mathbf{}\mathbf{28}\mathbf{}\overline{)\mathbf{g}\mathbf{}{\mathbf{CaCO}}_{\mathbf{3}}}\mathbf{}\left(\frac{1\overline{)\mathrm{mol}{\mathrm{CaCO}}_{3}}}{100.09\overline{)g{\mathrm{CaCO}}_{3}}}\right)\left(\frac{1\overline{)\mathrm{mol}{\mathrm{CaCl}}_{2}}}{1\overline{)\mathrm{mol}\hspace{0.17em}{\mathrm{CaCO}}_{3}}}\right)\left(\frac{110.98g{\mathrm{CaCl}}_{2}}{1\overline{)\mathrm{mol}{\mathrm{CaCl}}_{2}}}\right)$

g CaCl_{2} = 31.046 g

When calcium carbonate is added to hydrochloric acid, calcium chloride, carbon dioxide, and water are produced.

CaCO_{3}(s) + 2HCl(aq) → CaCI_{2}(aq) + H_{2}O(l) + CO_{2}(g)

How many grams of calcium chloride will be produced when 28.0 g of calcium carbonate are combined with 14.0 g of hydrochloric acid?

Which reactant is in excess and how many grams of this reactant will remain after the reaction is complete?

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